7.10 At 450K, Kp= 2.0 × 1010/bar for the given reaction at equilibrium.

2SO2(g) + O2(g) 2SO3 (g)

What is Kc at this temperature?

For the given reaction,
n=2-3=-1
T=450K
R=0.0831barLbarK-1mol-1
Kp=2.0×1010bar-1
Weknowthat,
Kp=KcRTn
2.0×1010bar-1=Kc0.0831lbarK-1mol-1×450K-1
Kc=2.0×1010bar-10.0831LbarK-1mol-1×450K-1
=2.0×1010bar-10.0831ILbarK-1mol-1×450K
=74.79×1010Lmol-1
=7.48×1011Lmol-1
=7.48×1011M-1