The enthalpy of reaction for the reaction

2H2(g)+O2(g)2H2O(l)isrH=-572kJmol-1

What will be standard enthalpy of formation of H2O(l)?


Given that,
2H2(g)+O2(g)2H2O(l),rH=?
This can be obtained by dividing the given authority by 2.
Therefore, rH(H2O)=-572kJmol-12=-286kJmol-1