5.12 Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar.
(R = 0.083 bar dm
3 K–1 mol–1).

                            Given,
n=4.0molV=5dm3p=3.32bar
R=0.083bardm3K-1mol-1

The temperature (T) can be calculated using the ideal gas equation as:
pV=nRT
T=pVnR
=3.32×54×0.083=50K
Hence, The requires temperature is 50 K.