5.8 What will be the pressure of the gaseous mixture when 0.5 L of H2 at 0.8 bar and 2.0 L of dioxygen at 0.7 bar are introduced in a 1L vessel at 27°C?

 

NEETprep Answer: 
                        

Let the partial pressure of H2 in the vessel be pH2.

Now,

p1=0.8barp2=pH2
V1=0.5LV2=1L

It is known that,

p1V1=p2V2
p2=p1V1V2
pH2=0.8×0.51
=0.4bar

Now, let the partial pressure of O2 in the vessel be pO2.

Now,

p10.7barp2=pO2=?
V1=2.0LV2=1L

p1V1=p2V2
p2=p1V1V2
pO2=0.7×201
=0.4bar

Total pressure of the gas mixture in the vessel can be obtained as:

ptotal=pH2+pO2
=0.4+1.4
=1.8bar

Hence, the total pressure of the gaseous mixture in the vessel is 1.8 bar.