5.2 A vessel of 120 mL capacity contains a certain amount of gas at 35 °C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at 35 °C. What would be its pressure?

Given,

Initial pressure, p1 = 1.2 bar

Initial volume, V1 = 120 mL

Final volume, V2 = 180 mL
Since the temperature remains constant, the final pressure (p2) can be calculated using Boyle’s law.

According to Boyle’s law, 

                          p1V1=p2V2
p2=p1V1V2
=1.2×120180bar
=0.8bar

Therefore, the pressure would be 0.8 bar.