2.37 The diameter of zinc atom is 2.6 Å.Calculate

(a) radius of zinc atom in pm and
(b) number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side lengthwise.

(a) Radius of zinc atom = Diameter/2

=2.6A2
=1.3x10-10m
=130x1012m=130pm

(b) Length of the arrangement = 1.6 cm
= 1.6 × 10-2 m
Diameter of zinc atom = 2.6 × 10-10 m
∴ Number of zinc atoms present in the arrangement

=1.6x10-2m2.6x10-10m
=0.6153x108m
=6.153x107