Ncert Exercises & Solutions

When the planet Jupiter is at a distance of \(824.7\) million kilometres from the Earth, its angular diameter is measured to be \(35.72''\) of arc. The diameter of Jupiter is:
1. \(1.43\times10^8~\text m\)
2. \(1.43\times10^8~\text {km}\)
3. \(1.43\times10^6~\text m\)
4. \(1.43\times10^6~\text{km}\)

Given angular diameter θ = 35.72= 35.72 x 4.85 x 10^-6 rad
= 173.242 x 10^-6 = 1.73 x 10^-4 rad
Diameter of Jupiter D = θ x d = 1.73 x 10^-4 x 824.7 x 10⁹ m
=1426.731 x 10³ = 1.43 x 10⁸ m

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