The length, breadth, and thickness of a rectangular sheet of metal are \(4.234\) m, \(1.005\) m, and \(2.01\) cm respectively. The area and volume of the sheet to correct significant figures are respectively:
1. | \(8.723 ~\text{m}^2, 0.0855 ~\text{m}^3\) |
2. | \(9.1 ~\text{m}^2, 0.855 ~\text{m}^3\) |
3. | \(8.72 ~\text{m}^2, 0.085 ~\text{m}^3\) |
4. | \(8.72 ~\text{m}^2, 0.0855~ \text{m}^3\) |
Hint: The area and volume must have \(3\) significant figures in its final value after calculation.
Step 1: Find the area and volume of the sheet to correct significant figures.
The area of the sheet is given by;
\(A=2(l\times b+b\times t+ t\times l) = 2(4.234\times 1.005+1.005\times 0.0201+0.0201\times 4.234)\)
\(\Rightarrow A= 8.72~\text{m}^2\)
The volume of the sheet is given by;
\(V = l \times b\times t= 4.234 \times 1.005 \times 0.0201\)
\(\Rightarrow V = 0.08552~\text{m}^3\)
The volume of the sheet to correct significant figures is given by;
\(V = 0.0855~\text{m}^3\)
Hence, option (4) is the correct answer.
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