Choose the incorrect statement from the given ones:

1. The volume of a cube of side \(1~\text{cm}\) is equal to \(10^{-6}~\text{m}^2\).
2. The surface area of a solid cylinder of radius \(2.0~\text{cm}\) and height \(10~\text{cm}\) is equal to \(1.5\times10^{4}~\text{mm}^2\).
3. A vehicle moving with a speed of \(18~\text{km/h}\) covers \(5~\text m\) in \(1~\text s\).
4. The relative density of lead is \(11.3\). Its density is \(11.3~\text{g/cm}^3\).
(a)
As we know, 1 m = 100 cm

So, 1 cm = 1/100 m=10-2m

The volume of the cube = 1 cm × 1 cm × 1 cm = =10-2×10-2×10-2m3=10-6m3

Hence, the volume of a cube of side 1 cm is equal to 10-6m3.

(b) The total surface area of a cylinder of radius r and height h,

S = 2πr(r + h).

Given that, r = 2 cm = 2 × 1 cm = 2 × 10 mm = 20 mm

h = 10 cm = 10 × 10 mm = 100 mm

S=2×3.14×20×20+100=15072=1.5×104mm2

(c) Using the conversion,

1 km/h = 518m/s

18km/h=18×518=5m/s

Therefore, distance can be obtained using the relation:

Distance = Speed × Time = 5 × 1 = 5 m

Hence, the vehicle covers 5 m in 1 s.

(d)The relative density of a substance is given by the relation,

Relative density = DensityofsubstanceDensityofwater

The density of water = 1 g/cm3

The density of lead = Relative density of lead × Density of water
                            = 11.3 x 1 = 11.3 g/cm3

Again, 1g = 11000kg

1cm3=10-6m3

1g/cm3=10-310-6kg/m3=103kg/m3

11.3g/cm3=11.3×103kg/m3