14.24 A body describes simple harmonic motion with an amplitude of 5 cm and a period of 0.2 s. Find the acceleration and velocity of the body when the displacement is
(a) 5 cm                (b) 3 cm                (c) 0 cm..

It is given in the questions that:

Amplitude,A=5cm=0.05m
Timeperiod,T=0.2s
Fordisplacement,x=5cm=0.05m
Acceleration:
a=-ω2x
=-2πT2x
=-2π0.22×0.05
=-5π2m/s2
Velocity:
v=ωA2-x2
=2πT0.052-0.052
=0
Fordisplacement,x=3cm=0.03m
Acceleration:
a=-ω2x
=-2πT2x
=-2π0.22=0.03
=-3π2m/s2
Velocity:
v=ωA2x2=2πTA2x2=2πT(0.05)2(0.03)2=2π0.2×0.04=0.4πm/s
Fordisplacement,x=0
Acceleration:
a=-ω2x=0
Velocity:
v=ωA2x2=2πTA2x2=2π0.2(0.05)20=0.5πm/s