If the RMS current in a \(50~\text{Hz}\) AC circuit is \(5~\text{A}\), the value of the current \(\dfrac{1}{300}~\text{s}\) after its value becomes zero is:

1. \(5\sqrt2~\text{A}\) 2. \(5\sqrt{\dfrac32}~\text{A}\)
3. \(\sqrt{\dfrac56}~\text{A}\) 4. \(\dfrac{5}{\sqrt2}~\text{A}\)
(b)Hint:Thecurrentvariesperiodicallyinthecircuit.
Step 1: Given,ν=50Hz,Irms=5A
t=1300s
WehavetofindI(t).
Step 2: I0=Peakvalue=2Irms=2×5
=52A
Step 3: I=I0sinωt=52sin2πνt=52sin2×50×1300
=52sinπ3=52×32=53/2A