A \(12~\text{pF}\) capacitor is connected to a \(50~\text{V}\) battery. How much electrostatic energy is stored in the capacitor?
1. \(3.0 \times 10^{-9}~\text J\)
2. \(6.0 \times 10^{-9}~\text J\)
3. \(1.5 \times 10^{-8}~\text J\)
4. \(3.0 \times 10^{-8}~\text J\)
Given,
Capacitance of the capacitor, C = 12pF = 12 x 10-12 F
Potential difference, V = 50 V
Electrostatic energy stored in the capacitor is given by the relation,
Therefore, the electrostatic energy stored in the capacitor is 1.5 x 10-8 J. was disconnected.
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