Q. No.1. \(1000~\text{N}\)
2. \(2500~\text{N}\)
3. \(1500~\text{N}\)
4. \(3500~\text{N}\)
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A ball of mass \(m\) falls from a height \(h\) onto the ground and rebounds to a height \(\dfrac{h}{4}\). The impulse on the ball from the ground has the magnitude:
| 1. | \(\dfrac{3}{4}m\sqrt{2gh}\) |
| 2. | \(\dfrac{5}{4}m\sqrt{2gh}\) |
| 3. | \(\dfrac{3}{2}m\sqrt{2gh}\) |
| 4. | \(\dfrac{1}{2}m\sqrt{2gh}\) |
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A wire connects two blocks of masses \(M\), \(2M\); both lying on a smooth horizontal plane.
When a force \(F_1\) is applied to \(2M\) as shown in figure 1, the wire just breaks. On the other hand, when \(F_2\) is applied to \(M\) as shown in figure 2,
the wire just breaks. Assume that the mass of the wire is negligible. Then:
| 1. | \(F_1 =F_2\) |
| 2. | \(F_1>F_2\) |
| 3. | \(F_1<F_2\) |
| 4. | Any of the above is possible |
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| 1. | \(\dfrac{3 g}{5} ~\text{down}\). | 2. | \(\dfrac{6 g}{5}\text{ down}\). |
| 3. | \(\dfrac{g}{5}\text{ down}\). | 4. | \(\dfrac{11 g}{5}\text{ down}\). |
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1. to the right.
2. to the left.
3. upward.
4. downward.
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| 1. | \(\dfrac{E_m}{m}=\dfrac{E_M}{M}\) | 2. | \(mE_m=ME_M\) |
| 3. | \(\dfrac{E_m}{m^2}=\dfrac{E_M}{M^2}\) | 4. | \(m^2E_m=M^2E_M\) |
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1. \(g\)
2. \(g~\text{sin}30^{\circ}\)
3. \(g~\text{cos}30^{\circ}\)
4. \(g~\text{tan}30^{\circ}\)
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1. \(F\)
2. \(2F\)
3. \(\sqrt2F\)
4. \(\dfrac{F}{\sqrt2}\)
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1. \(g\)
2. \(\dfrac{g}{2}\)
3. \(\dfrac{g}{\sqrt2}\)
4. \(g\sqrt2\)
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| 1. | \(\dfrac{g}{2}\) | 2. | \(\dfrac{g}{5}\) |
| 3. | \(\dfrac{2g}{5}\) | 4. | \(g\) |
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