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Q. No.Match List I with List II.
Choose the correct answer from the options given below:
1. A - III, B - IV, C - I, D - II
2. A - II, B - III, C - I, D - IV
3. A - III, B - IV, C - II, D - I
4. A - II, B - IV, C - I, D - III
| List I (Conversion) |
List II (Number of Faraday required) |
||
| A. | 1 mol of H2O to O2 | I. | 3F |
| B. | 1 mol of \(MnO^-_4\) to \(Mn^{2+}\) | II. | 2F |
| C. | 1.5 mol of \(Ca\) from molten \(CaCl_2\) | III. | 1F |
| D. | 1 mol of FeO to Fe2O3 | IV. | 5F |
1. A - III, B - IV, C - I, D - II
2. A - II, B - III, C - I, D - IV
3. A - III, B - IV, C - II, D - I
4. A - II, B - IV, C - I, D - III
Subtopic: Faraday’s Law of Electrolysis |
61%
From NCERT
NEET - 2024
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Mass in grams of copper deposited by passing 9.6487 A current through a voltmeter containing copper sulphate for 100 seconds is(Given : Molar mass of Cu: \(63 g mol^{-1}\) F = 96487 C)
1. 0.315 g
2. 31.5 g
3. 0.0315 g
4. 3.15 g
1. 0.315 g
2. 31.5 g
3. 0.0315 g
4. 3.15 g
Subtopic: Faraday’s Law of Electrolysis |
65%
From NCERT
NEET - 2024
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Given below are two statements:
In the light of the above statements, choose the correct answer from the options given below:
1. Both Statement I and Statement II are true
2. Both Statement I and Statement II are false
3. Statement I is true but Statement II is false
4. Statement I is false but Statement II is true
| Statement I: | \(2 \mathrm{~F}\) electricity is required for the oxidation of 1 mole \(\mathrm{H}_2 \mathrm{O}\) to \(\mathrm{O}_2\). |
| Statement II: | To get \(40.0 \mathrm{~g}\) of Aluminium from molten \(\mathrm{Al}_2 \mathrm{O}_3\) required electricity is \(4.44 \mathrm{~F}\). |
In the light of the above statements, choose the correct answer from the options given below:
1. Both Statement I and Statement II are true
2. Both Statement I and Statement II are false
3. Statement I is true but Statement II is false
4. Statement I is false but Statement II is true
Subtopic: Faraday’s Law of Electrolysis |
62%
From NCERT
NEET - 2024
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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R):
In the light of the above statements choose the correct answer from the options given below:
| Assertion (A): | In equation \(\Delta_{\mathrm{r}} \mathrm{G}=-\mathrm{nFE} _{\text {cell }}, \) value \(\mathrm{\Delta_rG }\) depends on n. |
| Reason (R): | \(\mathrm{E_{cell} }\) is an intensive property and \(\mathrm{\Delta_rG }\) is an extensive property. |
| 1. | (A) is False but (R) is True. |
| 2. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 3. | Both (A) and (R) are True and (R) is not the correct explanation of (A). |
| 4. | (A) is True but (R) is False. |
Subtopic: Relation between Emf, G, Kc & pH |
57%
From NCERT
NEET - 2023
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The conductivity of centimolar solution of KCl at 25°C is 0.0210 ohm–1 cm–1 and the resistance of the cell containing the solution at 25°C is 60 ohm. The value of the cell constant is:
| 1. | 3.34 cm–1 | 2. | 1.34 cm–1 |
| 3. | 3.28 cm–1 | 4. | 1.26 cm–1 |
Subtopic: Conductance & Conductivity |
77%
From NCERT
NEET - 2023
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The molar conductance of an electrolyte increases with dilution according to the equation:
\(\Lambda_{\mathrm{m}}=\Lambda_{\mathrm{m}}^{\circ}-\mathrm{A} \sqrt{\mathrm{c}} \)
Consider the following four statements:
Which of the above statements are correct?
\(\Lambda_{\mathrm{m}}=\Lambda_{\mathrm{m}}^{\circ}-\mathrm{A} \sqrt{\mathrm{c}} \)
Consider the following four statements:
| A: | This equation applies to both strong and weak electrolytes. |
| B: | The value of the constant A depends upon the nature of the solvent. |
| C: | The value of constant A is the same for both \(BaCl_2\) and \(MgSO_4\) |
| D: | The value of constant A is the same for both \(BaCl_2\) and \(Mg(OH)_2\) |
| 1. | (A) and (B) only | 2. | (A), (B), and (C) only |
| 3. | (B) and (C) only | 4. | (B) and (D) only |
Subtopic: Conductance & Conductivity |
55%
From NCERT
NEET - 2023
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The correct value of cell potential in volt for the reaction that occurs when the following two half cells are connected, is:
\(\mathrm{{Fe}_{ {(aq) }}^{2+}+2 {e}^{-} \rightarrow {Fe}({s}), {E}^{\circ}=-0.44{~V} }\)
\( \mathrm{{Cr}_2 {O}_7^{2-}{ }_{ {(aq) }}+14 {H}^{+}+6 e^{-} \rightarrow 2 {Cr}^{3+}+7 {H}_2 {O}},\)
\( \mathrm{{E}^{\circ}=+1.33 {~V}}\)
1. +1.77 V
2. +2.65 V
3. +0.01 V
4. +0.89 V
\(\mathrm{{Fe}_{ {(aq) }}^{2+}+2 {e}^{-} \rightarrow {Fe}({s}), {E}^{\circ}=-0.44{~V} }\)
\( \mathrm{{Cr}_2 {O}_7^{2-}{ }_{ {(aq) }}+14 {H}^{+}+6 e^{-} \rightarrow 2 {Cr}^{3+}+7 {H}_2 {O}},\)
\( \mathrm{{E}^{\circ}=+1.33 {~V}}\)
1. +1.77 V
2. +2.65 V
3. +0.01 V
4. +0.89 V
Subtopic: Electrode & Electrode Potential |
72%
From NCERT
NEET - 2023
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The molar conductance of a solution, given its conductivity (0.248 S m–1) and concentration (0.2 mol m–3) is:
1. 0.124 S cm2 mol–1
2. 1.24 S m2 mol–1
3. 124 S cm2 mol–1
4. 124 S m2 mol–1
1. 0.124 S cm2 mol–1
2. 1.24 S m2 mol–1
3. 124 S cm2 mol–1
4. 124 S m2 mol–1
Subtopic: Conductance & Conductivity |
From NCERT
NEET - 2023
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Given below are half-cell reactions:
\(\text{MnO}_{4}^{-}+8 \text{H}^{+}+5 \text{e}^{-} \rightarrow \text{Mn}^{2+}+4 \text{H}_{2} \text{O}, \)
\( \text{E}_{\text{Mn}^{2+}}^{\circ} / \text{MnO}_{4}^{-}=-1.510 \text{ V} \)
\( \frac{1}{2} \text{O}_{2}+2 \text{H}^{+}+2 \text{e}^{-} \rightarrow \text{H}_{2} \text{O}, \)
\( \text{E}_{\text{O}_{2} / \text{H}_{2} \text{O}}^{\circ}=+1.223 \text{ V}\)
Will the permanganate ion, \(\text{MnO}_{4}^{-}\) , liberate \(\text{O}_{2}\) from water in the presence of an acid?
1. No, because \(\text{E}_{\text {cell }}^{\circ}=-2.733 \text{ V}\)
2. Yes, because \(\text{E}_{\text {cell }}^{\circ}=+0.287 \text{ V}\)
3. No, because \(\text{E}_{\text {cell }}^{\circ}=-0.287 \text{ V}\)
4. Yes, because \(\text{E}_{\text {cell }}^{\circ}=+2.733 \text{ V}\)
\(\text{MnO}_{4}^{-}+8 \text{H}^{+}+5 \text{e}^{-} \rightarrow \text{Mn}^{2+}+4 \text{H}_{2} \text{O}, \)
\( \text{E}_{\text{Mn}^{2+}}^{\circ} / \text{MnO}_{4}^{-}=-1.510 \text{ V} \)
\( \frac{1}{2} \text{O}_{2}+2 \text{H}^{+}+2 \text{e}^{-} \rightarrow \text{H}_{2} \text{O}, \)
\( \text{E}_{\text{O}_{2} / \text{H}_{2} \text{O}}^{\circ}=+1.223 \text{ V}\)
Will the permanganate ion, \(\text{MnO}_{4}^{-}\) , liberate \(\text{O}_{2}\) from water in the presence of an acid?
1. No, because \(\text{E}_{\text {cell }}^{\circ}=-2.733 \text{ V}\)
2. Yes, because \(\text{E}_{\text {cell }}^{\circ}=+0.287 \text{ V}\)
3. No, because \(\text{E}_{\text {cell }}^{\circ}=-0.287 \text{ V}\)
4. Yes, because \(\text{E}_{\text {cell }}^{\circ}=+2.733 \text{ V}\)
Subtopic: Electrode & Electrode Potential |
From NCERT
NEET - 2022
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NEET 2025 - Target Batch
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NEET 2025 - Target Batch
Find the emf of the cell in which the following reaction takes place at 298 K:
\(\mathrm{Ni}(\mathrm{s})+2 \mathrm{Ag}^{+}(0.001 \mathrm{M}) \rightarrow \mathrm{Ni}^{2+}(0.001 \mathrm{M})+2 \mathrm{Ag}(\mathrm{s}) \)
\( \small{\text { (Given that } \mathrm{E}_{\text {cell }}^{\circ}=10.5 \mathrm{~V}, \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059 \text { at } \ 298 \mathrm{~K})} \)
1. 1.05 V
2. 1.0385 V
3. 1.385 V
4. 0.9615 V
Subtopic: Nernst Equation |
From NCERT
NEET - 2022
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NEET 2025 - Target Batch
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