Match the following:

COLUMN I COLUMN II
A.  88 g of CO2 1.       0.25 mol
B.  6.022×1023 molecules of H2O 2.       2 mol
C.  5.6 L of O2 at STP 3.       3 mol   
D.  96 g of O2 4.       1 mol
Codes
A B C D
1. 2 4 1 3
2. 1 2 3 4
3. 1 4 3 2
4. 4 1 3 2

Subtopic:  Moles, Atoms & Electrons |
 92%
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Match the following physical quantities with units.

Physical quantity Unit
A. Molarity 1. mol kg-1 
B. Molality 2. mol L-1
C. Pressure 3. Candela
D. Luminous intensity 4. Pascal

Codes

A B C D
1. 1 4 2 3
2. 2 1 4 3
3. 1 4 3 2
4. 4 1 3 2
Subtopic:  Introduction |
 94%
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Identify the reaction that does not obey the law of conservation of mass from the provided options.
 

1. 2Mg(s)+O2(g)2MgO(s)

2. C3H8(g)+O2(g)CO2(g)+H2O(g)

3. P4(s)+5O2(g)P4O10(s)

4. CH4(g)+2O2(g)CO2(g)+2H2O(g)

Subtopic:  Introduction |
 83%
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If the density of the solution is 3.12 g ml-1, then what will be the mass of the 1.5 ml solution in two significant figures?

1. \(4.4~\mathrm{g}\) 2. \(4680 \times 10^{3} ~\mathrm{g}\)
3. \(4.7~\mathrm{g}\) 4. \(46.80~\mathrm{g}\)
Subtopic:  Introduction |
 79%
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The empirical formula and molecular mass of a compound are CH2O and 180 g, respectively. The molecular formula of the compound is -

1.  C9H18O9 2.  CH2O
3.  C6H12O6 4.  C2H4O2
Subtopic:  Empirical & Molecular Formula |
 90%
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Mark the species among the following that contains the highest number of atoms.

1. 4 g He

2. 46 g Na

3. 0.40 g Ca

4. 12 g He

Subtopic:  Moles, Atoms & Electrons |
 85%
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If 500 mL of a 5 M solution is diluted to 1500 mL, the molarity of the resultant solution is: 

1. 1.5 M

2. 1.66 M

3. 0.017 M

4. 1.59 M

Subtopic:  Concentration Based Problem |
 82%
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Two students performed the same experiment separately, and each of them recorded two readings of mass, which are given below. The correct reading of mass is 3.0 g. On the basis of the given data, mark the correct option out of the following statements.

Students Readings
(i) (ii)
    A 3.01 2.99
    B 3.05 2.95

1. The results of both the students' are neither accurate nor precise.
2. The results of student A are both precise and accurate.
3. Student B's results are neither precise nor accurate.
4. The results of student B are both precise and accurate.

Subtopic:  Introduction |
 68%
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10 g of a silver coin, when dissolved completely in excess of conc. HNO3 gives 8.5 g of silver nitrate.
The percentage purity of the coin is:
(Molar mass of silver is 108g)
 

1. 25% 2. 54%
3. 67% 4. 100%
Subtopic:  Equation Based Problem |
 65%
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Assertion (A): 1 a.m.u = 1 .66 × 10−24 gram .
Reason (R): The actual mass of one atom of C-12 is equal to 1.99 × 10-23 g .
 
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. (A) is False but (R) is True.
Subtopic:  Moles, Atoms & Electrons |
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